When building a fence from a metal profiled sheet, the first thing you want to know is how much the building will cost. It is quite difficult to manually calculate the cost of a metal profile fence, but fortunately there are many construction sites where a special calculator will quickly and accurately calculate online how much it will cost to build a fence.
An example of a classic corrugated fence
Fences from a professional flooring are very popular. Firstly, it attracts at a fairly low price compared to fences that use brick, stone or wood. Secondly, it is carried out in a short time and without the use of complex tools and mechanisms.
The professional flooring is sheets of metal bent on special machines in the cold way. 
The undulating surface is obtained by rolling and adds rigidity to the sheet. In this case, the material is not heated. From above, the sheet is covered with a protective layer of polymers, plastoizol or zinc.
Varieties of corrugated board
Profile marking
Decking also differs in sheet thickness, wave height and width. On the market there are profiled sheets with the following markings:
- C - wall metal profile used for fences and wall cladding of buildings.
- H - bearing corrugated board, it is used as a coating for roofs and ceilings.
- HC is a universal metal profile with a wide range of applications, including for the construction of a fence.
After the letter marking comes a digital value that indicates the height of the ribs, then the width of the profiled sheet and the thickness of the steel layer without taking into account the coating.
All types of marking sheets of corrugated board
For the fence, the most suitable is corrugated board marked C: wave height is used up to 20 mm, steel thickness is at least 0.7 mm.
Factors determining the cost of a profiled sheet fence
The final price of a metal profile fence depends on many conditions. A strong influence on the cost will be the fact of who will be involved in the installation. If you entrust the installation of the fence to specialized companies, the price per linear meter of the fence will increase significantly. Self-installation can and will be long in time, but will save significant funds.
Often companies selling metal profiles offer their services for installing a fence and indicate the price per linear meter of corrugated board. In this case, the cost includes laying the foundation, complete installation of the fence, installation of gates and gates.
Depending on the type of foundation and supports, a corrugated fence can be installed at the following prices:
If you take up the installation of a fence from a corrugated board with your own hands, it is quite possible to master both the calculations and the installation yourself.
Calculation of the cost of a fence from a metal profile
The profiled sheet fencing consists of three main components: the foundation, the frame and the profiled metal sheets themselves. And, therefore, the amount of costs should include the costs of all these components.
Foundation for a corrugated fence
The foundation for a fence from a profiled sheet can be tape, columnar and tape-columnar.
The choice of foundation design is influenced by several conditions:
- Soil type;
- Depth of groundwater;
- The abundance of rain and the likelihood of floods in the region;
- Fence height.
It is not worth saving on materials for the foundation, and you should definitely take into account its type using the calculator for calculating the cost of a profiled sheet fence.
Calculation of the cost of a fence from corrugated board
frame cost
To calculate the cost of a corrugated fence, you need to take into account the cost of the frame, which consists of support posts and horizontal guides.
Or can act as support pillars. Also, brick and stone are often used to base the pillars, and such a fence is already approaching the elite and looks very solid and attractive. For the price of a fence with brick pillars, respectively, will be more expensive.
Almost every owner of a suburban area has to face the problem of installing fences around their possessions. There are many ways to solve this problem - for example, many wealthy owners of mansions prefer to build capital brick or stone fences. But the average owner of a suburban area still prefers a more “budget” option - a fence made of picket fence or sheet materials (corrugated board, slate, polycarbonate and the like). In this case, metal pipes are most often used as racks-supports.
Such supports can be purchased ready-made - a fairly wide range of such products is presented in stores. It will not be difficult for a good owner to make them on his own, by purchasing the required number of round or shaped pipes for this. The process of their installation and concreting is not too complicated. But since such work is planned, then some planning will be required, including the consumption of concrete for the installation of each of the supports. And since this amount is small, it is almost certain that the owner will knead the solution on his own, and he needs to know the amount of the original ingredients.
So, on a 2-meter span of a typical fence 2 meters high (i.e., on one fence post), the wind load acts:
F \u003d 2 x 2 x 38.9 \u003d 155.6 kgc
The load application point (L) is determined in the middle of the corrugated sheet (1 m) plus the distance from the bottom edge of the corrugated board to the ground (take 25 cm). Thus, the wind force acting on the fence post causes a bending moment at the point where the post leaves the ground (maximum loaded section) in the amount of:
M \u003d FLk \u003d 155.6 x 1.25 x 1.5 \u003d 291.75 kgf m
where k is the same margin of safety, which was mentioned above. In our case, k=1.5.
We emphasize that the above moment acting on the pole is calculated for a fence with our characteristics. Namely: the height of the corrugated board is 2 m, the pitch of the poles (span) is 2 meters, the distance from the lower edge of the profiled sheet to the ground is 0.25 m. Changing any of the parameters entails a change in the load on the pole and requires a mandatory recalculation!
Now we just have to choose such a pipe size, the bending strength of which overlaps the specified moment. The maximum bending moment of a metal beam is determined by the formula:
M = σW/1000
Where σ is the yield strength of the material (kgf / mm2), W is the section modulus (mm 3), and 1000 is for converting units from mm to meters.
The yield strength for steel St1ps, St10 (from which ordinary quality pipes sold in the markets are made) is 20-21 kgf / mm 2. The moment of resistance is calculated by the formula:
W \u003d π (D 4 -d 4) / 32D– for round pipe
W \u003d (H 4 -h 4) / 6H– for square pipe
We obtain the destructive bending moments for various pipe sizes:
round pipe
| Pipe outside diameter, mm | Wall thickness, mm | destructive moment, kgf m |
| 60 | 2 | 102,28 |
| 60 | 3 | 145,85 |
| 76 | 2,5 | 205,41 |
| 76 | 3 | 241,62 |
| 76 | 3,5 | 276,31 |
| 76 | 4 | 309,53 |
| 89 | 3 | 337,19 |
| 89 | 3,5 | 386,74 |
| 89 | 4 | 434,52 |
square pipe
| Outer pipe size, mm | Wall thickness, mm | destructive moment, kgf m |
| 60 | 2 | 173,64 |
| 60 | 2,5 | 211,63 |
| 60 | 3 | 247,61 |
| 60 | 3,5 | 281,64 |
| 60 | 4 | 313,8 |
| 80 | 3 | 457,23 |
| 80 | 4 | 586,92 |
It can be seen from the tables presented that for use as pillars for a solid fence with our initial parameters (step - 2 meters, profiled sheet height - 2 meters), a round pipe is suitable, starting from a standard size of 76x4 mm, square - starting from 60x4 mm (highlighted in green) . The higher the fence and the greater the distance between the posts, the more durable the pipe must be chosen.
The choice of a round or square pipe should be carried out not only on the basis of design and aesthetic preferences. It is necessary to take into account a number of engineering and economic factors. In more detail, the issues of choosing the section of fence posts are discussed in Prices for a corrugated fence
By fencing the perimeter or boundary of our household, we strive to hide from prying eyes. Having retired to their site, many owners are so obsessed with the idea of isolation from the outside world that they erect fences up to 5-6 meters in height. Such fences can interfere with those living in the neighborhood. In order to avoid disputes in this regard, the current legislation establishes the rules for the construction of fences, their height and location.
General criteria, what should be the height of the fence and how to calculate it
The presence of a fence, its height and material of manufacture, are always due to factors that create discomfort for the owner, which include:
- Annoying neighbors. Homeownership does not always border on friendly tenants.
- Potential penetration hazard. A high fence will become a reliable natural barrier for people plotting to steal your property. For this purpose, profiled sheet fences have become a popular option. With a small thickness of the material, the upper edge of the fence is sharp, which does not allow leaning on it. In turn, the smooth surface of the sheets further complicates penetration into your territory.
- Neighbor animals. This is especially noticeable in rural areas, where even chickens are able to fly over a fence up to 2 m high. In the absence of a fence in such an area, animals that have entered your garden can destroy the entire crop.
With so many reasons, the question arises: “why are high fences not common?” It should be noted that this is due to the following factors:
- The main one is the cost of materials for construction. It is easy to calculate that the construction of a three-meter fence will cost as much as the construction of two half-meter ones.
- The higher the fence, the more its wind load increases. To withstand the pressure of a strong wind, it is necessary to install a solid foundation and strong pillars, which means additional costs.
- The high height of the fence will create discomfort for your neighbors. Such a fence will create a large shadow, which will negatively affect the growth of green spaces. Also, this will cause shading of the premises in the neighbor's house.
- Restrictions established by law.
The established requirements for the construction of fences require us to:
- If the construction of the fence is carried out on the main highways of cities and villages, then the material for its construction must be agreed with the local authorities.
- The height of the fence separating the street or public area from your site should not exceed 220 cm from ground level.
- The material must not injure passers-by. Care must be taken that its surface does not contain a burr, skid and sharp protruding fragments. Building a fence from unpolished boards and decorating it with barbed wire would be too much.
- The fence separating neighboring territories should also not exceed a height of 2 m 20 cm, but there are certain nuances here:
- by agreement of neighbors, fencing from raspberry, currant, bindweed, ivy plants is allowed. However, the height of this living barrier should not exceed 150 cm;
- you need to install a fence that has a lattice look. For this, fences made of boards, gratings and nets are suitable, the area of \u200b\u200bthe gaps of which is at least 50%;
- if you are planning to build a blind fence (brickwork, prefabricated or monolithic concrete slab, profiled material), then without the consent of the neighbors, it cannot be higher than 75 cm;
- written permission from a neighbor will be required if you build a fence whose thickness exceeds 5 cm. Without it, with such parameters, you can build a fence within your territory;
- when installing a fence made of brick, concrete and other materials that form solid sections, care must be taken to build drainage systems and drainage systems. If rain or melt water causes flooding of the neighboring territory, then its residents have the right to go to court with a claim for the dismantling or demolition of the structure you have erected;
- when building a fence on your own, you need to understand that its poor-quality installation will annoy neighbors who will turn into enemies. It is unpleasant when, throughout the day, there is a continuous shadow from the fence in the windows or, for the same reason, the plants on the site wither.
When calculating the height of the fences, the material used for the posts and sections should be taken into account.
If the fence is made of chain-link mesh, then its height can be made more than two meters using profile pipes driven into the ground. The windage of such a fence is so small that at this point you can ignore it.
If a solid fence is erected, for example, from profiled sheets, then the effect of even a slight wind can deform the entire structure. To avoid this, you will need to lay a columnar or columnar-tape base.
When building fences made of stone or brick, you will also need a reliable foundation, as well as strengthening the pillars. As such, vertically mounted pipes with a treated surface are used, which are pre-concreted at the base.
Considering all of the above, it should be borne in mind that building codes and rules are not mandatory, but rather advisory in nature. It can only be enforced by local law.
Fence height standards listed in regional regulations may differ from recommended building codes. This is due to the fact that different regions of our country the sun has different elevation angles above the horizon. Differences in constant wind speeds in the regions are also taken into account, for example, a fence made of profiled sheets mounted on metal pipe poles will create a threat to life.
The height of the fence is not always limited by the norms. For example, in preschool children's institutions, it should be at least 160 cm, and in schools, bushes or other plants are additionally planted in front of them.
Linear meter - what is it and how to determine
To measure the means used, repair and construction processes, they use not an ordinary meter, but a special unit - a linear one. Often it is used to calculate the required amount of material for a fence under construction.
This unit of measure facilitates the calculation process and involves calculating only the length of the material, since its width is a standard size. From this it follows that this method is used to calculate the material in a rolled form.
The running meter is 100 cm. A large number of building materials have tags indicating the linear value. However, you can also meet with a note about the price per area. In this case, not only the length, but also the width is taken into account. A plot equal to 1m² consists of sides, each of which is 1m in size.
How to count a fence depending on the number of acres of a plot (5, 7, 9, 11, 20, etc.), examples
Before carrying out calculations, it is necessary to determine what kind of value - weaving. From the school mathematics course, it is known that the area of 1 weave (ar) is 10 10 \u003d 100 m², respectively, the area of a plot of 10 acres \u003d 100 10 \u003d 1000 m².
It should be noted that it is impossible to calculate the length of the sides with only area parameters. Each land owner has documents that indicate the size of the holdings. Therefore, a plot equal to 5 acres (500 m²) can have dimensions, for example: 10x50 m; 20x25 m; 5x100 m; 15x33.3 (499.5 m²), etc. each of the given dimensions is equal to or close to the indicated area. It follows that the multiplied values of each example will be equal to or close to 500 m². For example: 10 50= 500; 20 25=500; 5 100=500; 15 33.3=499.5. You need to understand that the plots are not perfectly square, rectangular or other regular shape. To determine the length of the sides, you need to add the length and width, after which the resulting value is multiplied by 2.
It is important to understand such a pattern that with the same area of \u200b\u200bthe figure, the values \u200b\u200bof the perimeters with different sizes of the sides will differ.
This fact is easy to verify with the help of a visual example. So, let's imagine that a plot of land equal to 4 acres has the form of four identical cells forming a square. In the image, we can see 8 outer sides of the cells. If we imagine that four cells are located horizontally, then the area of \u200b\u200bthe figure will not change, and there will be the same 4 acres. However, if you look closely, then in this case we will see not 8 external sides, but 10. This illustrative example explains the difference in the perimeters of the figure with the same area.
Substitute the available parameters: (10 + 50) 2 = 120 m - this is the total length of the fence on the site with a side size of 10x50x10x50 m. Accordingly: (20 + 25) 2 = 90 m; (5+100) 2=210 m; (15+33.3) 2=499.5 m.
The same principle applies to the calculation of fences for plots with other sizes. For example, a territory with an area of 7 acres (700 m²) will have side dimensions: 26.5x26.4 m (699.6 m²); 20x30 m; 10x60 m; 6x100 m, etc. Let's make a calculation: (26.5 + 26.4) 2 = 105.8 m; (20+30) 2=100 m; (10+60) 2=140 m; (6+100) 2=112 m.
A plot of 9 acres (900 m²) can have the following dimensions: 30x30 m; 10x90 m; 40x22.5 m; 15x60 m, etc. We make the calculation: (30+30) 2=120 m; (10+90) 2=200 m; (40+22.5) 2=125 m; (15+60) 2=150 m.
A territory of 11 acres (110 m²) can have the following dimensions: 50x20.2; 10x110m; 30x3.7 (111m²). We calculate: (50 + 20.2) 2 = 140.4 m; (10+110) 2=140 m; (30+3.7) 2=67.4 m.
An area equal to 20 acres (2000 m²) may contain plots of the following sizes: 10x200m; 5x400m; 40x50m; 70x28.6 (2002 m²). Let's make a calculation: (10+200) 2=420 m; (5+400) 2=810 m; (40+50) 2=180 m; (70+28.6) 2=197.2 m.
A plot of land equal to 27 acres (2700 m²) can have the following dimensions: 130x20.8 m; 10x270 m; 70x38.6 (2702 m). We make the calculation: (130 + 20.8) 2 = 301.6 m; (10+270) 2=560 m; (70+38.6) 2=217.2 m.
How to calculate the material for the fence (with specific examples)
To understand how in practice the required material is calculated in linear meters, it is better to consider this with an example. Our task is to determine how much material is required to make a solid fence. First you need to set the total length of the sides of the future building. Suppose that the proposed site on which the fence will be installed has dimensions of 20x50 m. Since the site is rectangular, you need to add these values and multiply the result by half: (50 + 20) 2 \u003d 140 - the sum of the lengths of all sides of the rectangle or the total fence length. As a result of mathematical calculations, it was found that it occupies an area equal to 10 acres or 100 m².
For further calculations, you will need the parameters of each type of material, as well as the dimensions and design of the future structure. As an example, calculations will be made of materials for a fence made of: bricks, picket fence, boards and metal profile sheets.
Brick
To calculate the number of bricks for this fence, information is needed not only on the width and height of the spans, but also on the parameters of the pillars, since they will be built from the same material.
For example, the fence will be built of red brick with dimensions of 250x120x65 cm. The total length of the fence is 140 m.
The fence will have a basement level, consisting of four rows of bricks. The basement, located under two pillars and one span, contains 216 bricks. Plinth length - 4315 mm.
One of the masonry layers similar to each other of each pillar consists of five bricks. The height of the column and the span located on the basement is 1625 mm, which is 25 rows. Width of a column from the front side of 500 mm.
The width of the fence span is 3500 mm. The laying will be carried out to the width of one brick in 14 rows.
The available parameters are enough to make a calculation and find out how many bricks are needed to build the entire fence.
Let's start with the calculations. First of all, you need to establish how many bricks you need for the basement of the entire fence:
To do this, you need to divide its total length by the length of the brick: 14000: 25 = 560 bricks will be required for one row along the entire length. Since the basement part consists of masonry three bricks wide and 4 rows high, then: 560 3 4 = 6720 pieces of bricks will be required for the base of the entire fence.
Now we calculate the number of posts for the entire fence. To do this, subtract the distance between the midpoints of two pillars from the total length of the fence: 14000:400=35 spans and 36 pillars, respectively. It should be borne in mind that there will be one more pillars, since the span on both sides is reinforced with a brick support.
Now you need to determine the number of bricks in one column. To do this, you need to multiply their number in one row by 25 rows: 5 25 \u003d 125 pieces. We multiply the resulting value by the number of all pillars: 125 36 = 4500 bricks will be required to build all the fence posts.
We do the calculation of the amount of material for the spans of a brick fence. We know that the height of the span contains 25 rows, and each of them has 14 bricks. We make a calculation by multiplying these values: 25 14 = 350 bricks are needed for laying one span of the fence. We multiply this result by the total number of spans: 350 35 = 12250 bricks.
profiled sheets
Sheets of profiled metal with the same height and width equal to 200x100 cm were chosen as the main material for the fence.
It is easy to calculate the amount of profiled material for a fence 140m long. This requires 140 sheets. This simple calculation is acceptable for a solid fence made of such material. If the design of the fence provides for protruding supports or other elements, these nuances should be taken into account, since the width of the spans will be reduced. Accordingly, less profiled metal is required.
foundation concrete
Concrete is most often used for the base of the fence. The shape of the foundation has its own characteristics, and resembles several connected geometric shapes, such as a cylinder, a cube and a rectangular parallelepiped. This form of foundation implies a strip-column base for fences made of heavy materials. To make accurate calculations of the required amount of concrete, you need to remember the school geometry course, namely the formulas for the volumes of these figures. For convenience, calculations will be made for each figure separately.
To find out the volume of concrete for a columnar base, you need to apply the formula for calculating the volume of a cylinder, which looks like this: V \u003d πR²h, where π is the mathematical value of the geometric number equal to 3.14; R is the radius of the base of the cylinder; h is the height of the cylinder. The optimal dimensions for such a foundation are shown in the image.
Let's substitute the values: 3.14 ∙ 0.125² ∙ 0.5 \u003d 0.39 m³ you will need a mixture for one concrete pile.
Now let's make a calculation for a cubic foundation located under the pillars. To do this, you need to use the formula for calculating the volume of a cube, in which the length - L, height - H, width - S are multiplied: V=L∙H∙S. Let's substitute the values: 0.3∙0.3∙0.3=0.027m³ - concrete is needed for one base under the pillar.
Now you need to add the obtained values \u200b\u200bto find out how much mixture is needed for a foundation fragment consisting of the previously described figures: 0.39 + 0.027 + 0.129 \u003d 0.456 m³
By doing these simple calculations, you will get the exact parameters of the future foundation. To find out how much concrete is needed for the entire fence, you need to multiply the resulting value by the number of pillars in the entire fence structure. It should be borne in mind that the number of spans will be one less than the number of pillars. We previously established that the fence, which is 140 m long, will have 35 spans and 36 posts. Now it is easy to calculate the total volume of concrete required to install the foundation of the entire fence. For this: 0.456 ∙ 36 = 16.415 m³, but since the number of spans is one less, it is necessary to subtract the volume parameters for one span from this figure: 16.415–0.129 = 16.286 m³ of concrete will be required to fill the tape-columnar base for the entire fence.
Foundation reinforcement
Reinforcing bars are used to strengthen the base of the fence. Before pouring the foundation, a metal structure is made from this material in the form of four longitudinal rods and transverse elements (clamps) for the base tape, and four rods for its pillars.
As we already know, in a 140 m long fence there will be 36 pillars with 35 spans. The distance from the beginning of one base of the pillar to the end of the second is 300 cm. The distance between the transverse structural elements is 80 cm. The height and width of the clamps are 25 cm each. Their number for one span is 4 pieces. Using these data, it is easy to calculate the amount of reinforcement.
First you need to determine how many meters of metal rods will be required for one pole and span.
For a tape of one span:
- 300∙4=1200 cm - longitudinal rods;
- 25∙4∙4=400 cm - transverse elements;
- 50∙4=200 cm - rods for a concrete pillar;
- 1200 + 400 + 200 \u003d 1800 cm or 18 m of reinforcement will be required for one span and pole.
Now it is easy to calculate how many metal rods are required for the entire fence. To do this, you need to multiply the resulting value by the number of sections of the entire fence. As we already know, there are 35 of them, therefore: 18 ∙ 35 = 630 m of material will be required to reinforce the foundation for the fence.
Fence
The amount of material required for picket fences depends on the width of the material, the distance between the boards, the way they are arranged, and, accordingly, on the length of the fence itself.
It should be noted that when installing a picket fence, the distance between its elements can be done differently. However, the fence will look more aesthetically pleasing in which the gap between the pickets will not exceed their width.
The width of the fence may be different, depending on the individual order of the consumer. If we are talking about a European fence, then in this case there are standards. The width of this material can be in the range from 70 to 170 mm.
To calculate the amount of a fence for a fence, you need to use the following formula: K \u003d A / (A1 + B) where A is the length of the entire fence, A1 is the width of the fence, B is the gap between the planks.
Suppose that the length of the fence is 140 m, the width of the fence is 120 mm, and the gap between them is 80 mm, then according to the formula, the calculation of the amount of material will be expressed in the following example: K = 140 / (0.12 + 0.08) = 700 pieces .
You can always reduce the cost of materials if you make the distance between the fences a little more, but within reasonable limits.
In the case when the fence provides for the location of pickets on both sides in a checkerboard pattern, then the previously obtained result must be doubled.
Boards
The use of this material implies the installation of fence elements in a vertical or horizontal position. As in the case of the picket fence, the number of boards in a vertical position is calculated using the specified formula. When fastening horizontally, the length of the sections and the material itself, as well as the length of the fence, should be taken into account.
For fences I use unedged and edged boards.
In the first case, the material is not stripped of bark, has a length of about 600 cm, a width of 100 to 500 mm. Such boards require additional processing and drying before use. Accordingly, such material has a low price, but it will take time to bring it to the proper state.
Edged boards are made with a width of 100 to 150 mm, a thickness of 20 - 25 cm. This material does not require additional drying and sanding. The surface of such boards is smooth, can be made in the form of a semicircular profile. For the manufacture of boards I use noble types of wood, such as, for example: oak or larch. Edged boards are an expensive material ready for use.
When calculating the material installed horizontally, the values \u200b\u200bof the width and length of the board, as well as the length of the entire fence, are used. Let's say the fence will be 140 m long. The width of one section is 3 m, and its height is 2.5 m, the distance between the boards will be 5 cm.
Using these parameters, it is necessary to determine how many boards are needed for horizontal placement in one section. To do this, you need to add the width of one board with the provided distance between the wood, after which the height of the section is divided by the resulting value: 2.5: (0.15 + 0.05) \u003d 2.5: 0.2 \u003d 12.5 pieces.
Then, to find out the total amount of material, you must first know how many sections will be in the fence. To do this, its length must be divided by the width of one section: 140: 3 \u003d 46.6 sections. Now we multiply this value by the number of boards in one section: 46.6 ∙ 12.5 = 582.5 boards will be required to build a fence 140 m long, 2.5 m high, with gaps between the boards equal to 5 cm.
Rivets and screws
To fix the elements of the fence, rivets, nails or self-tapping screws are used. Rivets are most often used during the installation of a eurostudent, and nails and self-tapping screws are most often used for wood. Having calculated the number of fence elements, it is easy to find out how much consumable material is required.
It should be noted that the required number of rivets, nails or self-tapping screws depends on the number of installed logs, the method of fastening and the material of the fence.
If the fence consists of a euro fence, then with two transverse lags, two rivets are sufficient. When installing a wooden picket fence or boards on two lags, you will need 4 screws or nails - two for each cross member.
Let's make a calculation for a fence 140 m long from a picket fence. As we know, 700 shtaketins are required for such a fence. Since for one picket on two lags 4 screws or nails are required, then: 700 ∙ 4 = 2800 pieces.
It should be borne in mind that consumables should always be purchased with a margin.
Carrying out accurate calculations during the construction of the fence will ensure the reliability of its design and save you from extra cash costs. By learning how to make these simple calculations, you will be able to give the right advice, which will help your loved ones or neighbors.
In order to deliver excellent, strong and attractive, it is necessary to correctly calculate the amount of material that will be needed during the work. It is on this that the reliability of the fence itself, the time spent on the entire construction process, and the financial costs of delivery, preparatory work, and installation of the fence will depend.
In our article, we will consider exactly what factors affect the calculation of components for fencing, what the cost of such a construction can be.
Calculation factors: building a new fence
In order to calculate the profiled sheet required for future construction and other components, it is imperative to take into account some factors. We always remember that any fence is an individual design, even when using standard materials.
But even with the simplest forms, the fence will consist not only of a profiled sheet, but also of support pillars and cement for pouring the support, transverse rows (lag, which give the structure additional strength and rigidity). Similar constructions are impossible without a gate or a small gate.
For fences, it is used with a wave height of ten to twenty millimeters, which can be simple galvanized (the cheapest option) or with a polymer color coating on one or two sides (the cost rises by about forty percent).
The support posts are made of a square profile pipe, the cross section of which depends on the height of the fence.
Decking allows you to make fences up to eight meters high, which does not affect strength. Logs are also needed, the number of which can be different and on which the corrugated board will be attached, fastener elements: self-tapping screws and steel rivets for joints.
How much does a profiled fence cost?
So, how much can a corrugated fence cost? First of all, it is necessary to take into account the length of the future fence, height, type of construction (with a foundation, without a foundation, combined options).
The main elements that will make up the financial costs:
- , which can be simple galvanized or polymer-coated. Best suited PS-10, PS-20.
- Logs (crossbars). Economy option - logs made of wood, the most durable - from a profile pipe. The number of lags, or rows, depends on the height of the structure.
- Foundation for support pillars (you can not do it, but it will be more reliable with the foundation).
For example, we calculate the material for a fence with a height of two meters and a length of thirty linear meters. In order to correctly calculate the number of components, we need to decide on the design of the fence itself. In this case, it will be a simple fence with support posts that will be cemented in the pits.
We take the PS-10 brand, which is ideal for such work. The total width of the sheet is 1180 millimeters, and the working width is 1140 millimeters. With a total length of the future building of thirty linear meters, we will need twenty-seven sheets. We calculate it this way: divide the length by the usable width and get a value of 26.32 sheets.
The resulting figure must be rounded up, that is, we get twenty-seven sheets. The total area of this product will be equal to 63.72 square meters, which is calculated as follows: the number of sheets is multiplied by the total width and the height of the future fence.
Now we need to calculate the number of pipes for the support pillars, we take a pipe with a cross section of twenty by forty millimeters. We will need thirteen pillars of two meters and eighty centimeters, that is, 36.4 linear meters. It is calculated in this way: the length of the future fence (thirty linear meters) is divided by the length of one span (two and a half meters).
We get a value of twelve spans, that is, we need one more pillars - thirteen pieces.
When buying, it is best to immediately ask the seller to cut the poles, which will reduce the cost of delivery and eliminate the need for self-cutting pipes on the site (that is, we will not need some tools).
For logs (crossbars), it is best to take a profile pipe with a cross section of twenty by twenty millimeters. We will need three rows of logs (since the height of the fence is two meters). We calculate the total number in this way: we multiply thirty linear meters (fence length) by three (number of rows) and we get the number of lags - ninety linear meters of material.
For fixing the support pillars, we will need two bags of cement, sand and gravel. For fastening corrugated board - roofing screws at the rate of up to eight pieces per square meter.
Now we calculate the total cost using a conventional calculator:
- corrugated board for the fence - about 14,450 rubles;
- profile pipe for cross members - up to 4800 rubles;
- pipe for support pillars - up to 2,590 rubles;
- cement, sand, gravel - from 800 rubles;
- self-tapping screws, the cost of which may be different.
The cost of delivery of the order will depend on the mileage and the person who carries it out (seller or buyer).
As we can see, the calculation of products under can be done using a conventional calculator: no complex formulas and calculations are carried out here. But when making calculations, it is necessary to take into account all the above factors that will help make this process more accurate.
